Math Problem Statement

(2 −3 ) 0 ×2 −2 ?

Solution

The expression you provided is:

(23)0×22(2^{-3})^0 \times 2^{-2}

Step 1: Simplify (23)0(2^{-3})^0

By the zero exponent rule, any number raised to the power of 0 is 1:

(23)0=1(2^{-3})^0 = 1

Step 2: Multiply by 222^{-2}

Now, multiply this by 222^{-2}:

1×22=221 \times 2^{-2} = 2^{-2}

Step 3: Evaluate 222^{-2}

To simplify 222^{-2}, we use the negative exponent rule: an=1ana^{-n} = \frac{1}{a^n}:

22=122=142^{-2} = \frac{1}{2^2} = \frac{1}{4}

Final Answer:

The value of the given expression is:

14\boxed{\frac{1}{4}}

Would you like any further explanation or details?

Here are some related questions you might find interesting:

  1. What is the general rule for exponents with negative bases?
  2. How do you simplify expressions with both positive and negative exponents?
  3. What is the zero exponent rule and how is it applied?
  4. Can negative exponents apply to fractions and how?
  5. What is the difference between powers of zero and powers of one?

Tip: Negative exponents indicate division, not negative values—always think of it as the reciprocal.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Exponents
Zero Exponent Rule
Negative Exponents

Formulas

a^0 = 1 (Zero Exponent Rule)
a^{-n} = \frac{1}{a^n} (Negative Exponent Rule)

Theorems

Zero Exponent Theorem
Negative Exponent Theorem

Suitable Grade Level

Grades 8-10